18x^2-21x-49=0

Solution for 18x^2-21x-49=0 equation:

18x^2-21x-49=0

a = 18; b = -21; c = -49;
Δ = b2-4ac
Δ = -212-4·18·(-49)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-63}{2*18}=\frac{-42}{36}
=-1+1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+63}{2*18}=\frac{84}{36}
=2+1/3
$